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show that (m+n)I(m,n) = m I(m
-1,n-1) +
(cosx)^m*sin (nx) where I(m,n ) = ∫ (cosx)^m * cos (nx) dx ---------------------------------------------- ----------------------------------------------- use integration by parts for one step and then try to change sinxsin(nx) and extract cosnx using the formulae for cos(nx-x) since n-1 is hinted to in the question answer and some steps are given below ================ * * ================ ![]() ![]() (trig. formulae) |
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