integral of (x² +1) / [(x+3)(x-1)²] using partial fractions

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integral of (x²+1) / [(x+3)(x-1)²] using partial fractions

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******* 1 1	integral of (x² +1) / [(x+3)(x-1)²] using partial fractions ---------------------------------------------- ----------------------------------------------- first of all decompose into partial fractions and integrate term by term for (x-1)² you will require two terms of the form A / (x-1) + B /(x-1)² to find A, B, C remember to multiply both sides with just [(x+3)(x-1)²] before putting values for x or comparing coefficients answer and some steps are given below ================ * * ================ other problems on applications of integration like area ,volume etc integration formulae problems on integration
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