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integral of 1 / sqrt[4 + 3x -
x² ] ---------------------------------------------- ----------------------------------------------- integrate after completing the square to make the coefficient of x² (+1) , take -1 common , but it remains inside the sqrt sign to get sqrt [ - ( x² -3x - 4)] now take half the coefficient of x , that is half of (-3) to get [x- (3/2) ]² and then adjust the constant term and finally re introduce the -1 taken out earlier answer and some steps are given below ================ * * ================ ![]() other problems on applications of integration like area ,volume etc integration formulae problems on integration |
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