integral of 1 / [ (x² +2)²] using trigonometric substitution

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integral of 1 / [ (x² +2)²] using trigonometric substitution
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******* 1 1	.∫ 1 / [ (x² +2)²] dx ---------------------------------------------- ----------------------------------------------- use x = sqrt(2) tan u as substitution find dx and simplify use trigonometric manipulation to change cos²u and integrate to change back to x use a right triangle and tanu =x /sqrt2 with one angle(not right angle) as u opp. as x , adjacent as sqrt2 so that hypotenuse is sqrt (x² +2) find sinu and cosu from that triangle to get rid of u answer and some steps are given below ================ * * ================ integration formulae more problems on integration
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